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4.9x^2+25x=-9.8
We move all terms to the left:
4.9x^2+25x-(-9.8)=0
We add all the numbers together, and all the variables
4.9x^2+25x+9.8=0
a = 4.9; b = 25; c = +9.8;
Δ = b2-4ac
Δ = 252-4·4.9·9.8
Δ = 432.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{432.92}}{2*4.9}=\frac{-25-\sqrt{432.92}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{432.92}}{2*4.9}=\frac{-25+\sqrt{432.92}}{9.8} $
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